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Differential Equations

JEE Main 2024 (Online) 5th April Evening ShiftNumericalMedium📈 Topic in 67% papers+4
Ques. 1JEE Main 2024, 5 April (Evening Shift)

Let y = y(x) be the solution of the differential equation dydx + 2x (1 + x2 )2y = xe 1 (1 + x2 ); y(0) = 0. Then the area enclosed by the curve f(x) = y(x)e- 1 (1 + x2 ) and the line y - x = 4 is .

Answer

18

Solution

Linear D.E.: 2x(1 + x2)2 dx = - 11 + x2 I.F. = e-1/(1 + x2)

y e-1/(1 + x2) = x e1/(1 + x2) e-1/(1 + x2) dx = x22 + C

y(0) = 0 C = 0 f(x) = y(x) e-1/(1 + x2) = x22

With y = x + 4: x22 = x + 4 x2 - 2x - 8 = 0 x = -2, 4

[figure]

Area = -24 (x + 4 - x22 )dx = [ x22 + 4x - x36 ]-24

= 403 - (- 143 ) = 18

Answer: 18

Keep practising — Differential Equations

Ques. 2JEE Main 2024, 4 April (Morning Shift)

If the solution y=y(x) of the differential equation (x4+2x3+3x2+2x+2 )dy- (2x2+2x+3 )dx=0 satisfies y(-1)=- 4, then y(0) is equal to :

  1. - 12
  2. 2
  3. 0
  4. 4
Ques. 3JEE Main 2024, 4 April (Morning Shift)

Let the solution y=y(x) of the differential equation dydx-y=1+4 x satisfy y( )=1. Then y ( 2 )+10 is equal to .

Ques. 4JEE Main 2024, 4 April (Evening Shift)

Let y = y(x) be the solution of the differential equation (x2 + 4)2dy + (2x3y + 8xy - 2)dx = 0. If y(0) = 0, then y(2) is equal to

  1. 2
  2. 8
  3. 16
  4. 32
Ques. 5JEE Main 2024, 4 April (Evening Shift)

Let y = y(x) be the solution of the differential equation (x + y + 2)2 dx = dy, y(0) = -2. Let the maximum and minimum values of the function y = y(x) in [0, 3 ] be and , respectively. If (3 + )2 + 2 = + 3, , Z, then + equals .

Ques. 6JEE Main 2024, 1 February (Morning Shift)

Let y=y(x) be the solution of the differential equation dydx=2x(x+y)3-x(x+y)-1, y(0)=1. Then, ( 1 2+y ( 1 2 ) )2 equals :

  1. 44+ e
  2. 33- e
  3. 21+ e
  4. 12- e
Ques. 7JEE Main 2024, 1 February (Morning Shift)

If x=x(t) is the solution of the differential equation (t+1)dx= (2x+(t+1)4 )dt, x(0)=2, then, x(1) equals .

Ques. 8JEE Main 2024, 1 February (Evening Shift)

Let be a non-zero real number. Suppose f: R R is a differentiable function such that f(0)=2 and x - f(x)=1. If f (x)= f(x)+3, for all x R, then f (- e 2 ) is equal to :

  1. 7
  2. 9
  3. 3
  4. 5
Ques. 9JEE Main 2024, 1 February (Evening Shift)

If dxdy= 1+x-y2y,x(1)=1, then 5x(2) is equal to .

Ques. 10JEE Main 2024, 31 January (Morning Shift)

Let y=y(x) be the solution of the differential equation dydx= ( x)+y x( x- x x), x (0, 2 ) satisfying the condition y ( 4 )=2. Then, y ( 3 ) is

  1. 3 (2+ e 3 )
  2. 3 (1+2 e 3 )
  3. 3 (2+ e 3 )
  4. 32 (2+ e 3 )
Ques. 11JEE Main 2024, 31 January (Morning Shift)

The solution curve of the differential equation y dxdy=x ( e x- e y+1 ), x>0, y>0 passing through the point (e, 1) is

  1. | e yx |=y2
  2. | e yx |=x
  3. | e xy |=y
  4. 2 | e xy |=y+1

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