Let a and b be real constants such that the function f defined by f(x)= casesx2+3x+a, & x 1\ bx+2, & x>1 cases be differentiable on R. Then, the value of -22f(x) dx equals
- 21
- 19/6
- 17
- 15/6
Answer
(3) 17
Solution
Continuity at x=1: 1+3+a=b+2 a=b-2
Differentiability at x=1: (2x+3)x=1=b b=5, a=3
-22f(x) dx= -21(x2+3x+3) dx+ 12(5x+2) dx
= [ x33+ 3x22+3x ]-21+ [ 5x22+2x ]12
= ( 296+ 83 )+ (14- 92 )= 152+ 192=17
Answer: (3)