All five letter words are made using all the letters A, B, C, D, E and arranged as in an English dictionary with serial numbers. Let the word at serial number n be denoted by Wn. Let the probability P(Wn) of choosing the word Wn satisfy P(Wn) = 2 P(Wn-1), n > 1. If P(CDBEA) = 2 2 -1, , N, then + is equal to
Answer
183
Solution
Number of words = 5! = 120
P(Wn) = 2n-1P(W1) and n=1120P(Wn) = 1
P(W1)(2120 - 1) = 1 P(Wn) = 2n-12120-1
Rank of CDBEA:
Words beginning with A or B: 2 4! = 48
Beginning with C, then A or B: 2 3! = 12
Beginning with CD, then A: 1 2! = 2
Beginning with CDB, then A: 1 1! = 1
rank of CDBEA = 48 + 12 + 2 + 1 + 1 = 64
P(CDBEA) = 2632120-1
= 63, = 120
+ = 183
Answer: 183