Two immiscible liquids of refractive indices 85 and 32 respectively are put in a beaker as shown in the figure. The height of each column is 6 cm. A coin is placed at the bottom of the beaker. For near normal vision, the apparent depth of the coin is 4 cm. The value of is . [figure]
Answer
31
Solution
happ = h1 1 + h2 2
each layer adds its own (real depth ÷ μ)
= 68/5 + 63/2 = 154 + 4
= 314 cm
= 31
Answer: 31