A force is represented by F=ax2+bt 12 where x= distance and t= time. The dimensions of b2/a are:
- [ ML2 T-3 ]
- [ ML3 T-3 ]
- [ MLT-2 ]
- [ ML-1T-1 ]
Answer
(2) [ ML3 T-3 ]
Solution
only quantities of the same dimensions can be added, each term has the dimensions of force, MLT-2
[a]= [F][x2]= MLT-2L2= ML-1T-2
[b]= [F][t1/2]= MLT-5/2
[ b2a ]= M2L2T-5 ML-1T-2
= ML3T-3
Answer: (2)