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If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is 10-2 MeV. (Given 1 u = 931 MeV/c2, atomic mass of helium = 4.002603 u)
727
3 42He 126C; atomic mass of 12C = 12 u (definition of u)
m = 3 4.002603 - 12 = 0.007809 u
Q = 0.007809 931 MeV
= 7.27 MeV = 727 10-2 MeV
Answer: 727
Which of the following nuclear fragments corresponding to nuclear fission between neutron (01n ) and uranium isotope (92235U ) is correct :
The disintegration energy Q for the nuclear fission of 235U 140Ce + 94Zr + n is MeV. Given atomic masses of 235U : 235.0439 u; 140Ce : 139.9054 u, 94Zr : 93.9063 u; n : 1.0086 u, Value of c2 = 931 MeV/u.
The radius of a nucleus of mass number 64 is 4.8 fermi. Then the mass number of another nucleus having radius of 4 fermi is 1000x, where x is .
From the statements given below : Choose the correct answer from the options given below :
The mass defect in a particular reaction is 0.4 g. The amount of energy liberated is n 107 kWh, where n= . (speed of light =3 108 m/s)
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is :
A nucleus has mass number A1 and volume V1. Another nucleus has mass number A2 and Volume V2. If relation between mass number is A2=4A1, then V2V1= .
In a nuclear fission reaction of an isotope of mass M, three similar daughter nuclei of same mass are formed. The speed of a daughter nucleus in terms of mass defect M will be :
The explosive in a Hydrogen bomb is a mixture of 1H2, 1H3 and 3Li6 in some condensed form. The chain reaction is given by 3Li6+0n1 2He4+1H3 1H2+1H3 2He4+0n1 During the explosion the energy released is approximately [Given ; M(Li)=6.01690 amu, M (1H2 )=2.01471 amu, M (2He4 )=4.00388 amu, and 1 amu=931.5 MeV]
In a nuclear fission process, a high mass nuclide (A 236) with binding energy 7.6 MeV/Nucleon dissociated into middle mass nuclides (A 118), having binding energy of 8.6 MeV/Nucleon. The energy released in the process would be MeV.