The sum of the spin only magnetic moment values (in B.M.) of [Mn(Br)6]3- and [Mn(CN)6]3- is .
Answer
7.5 to 7.8
Solution
Both contain Mn3+ (3d4); = n(n+2) B.M.
Br- (weak field): high spin t2g3eg1, n = 4 ⇒ = 24 = 4.90 B.M.
CN- (strong field): low spin t2g4, n = 2 ⇒ = 8 = 2.83 B.M.
Sum = 4.90 + 2.83 = 7.73 B.M.
Answer: 7.73