The resistance of an ammeter is 13 and its scale is graduated for a current upto 100 amps. After an additional shunt has been connected to this ammeter it becomes possible to measure currents upto 750 amperes by this meter. The value of shunt-resistance is
- 2
- 0.2
- 2 k
- 20
Answer
(1) 2
Solution
Current through the ammeter Ig = 100 A, total current I = 750 A.
Current through the shunt = I - Ig = 650 A
Shunt and ammeter are in parallel (same p.d.):
Ig G = (I - Ig)S
S = 100 13650 = 2
Answer: (1)