The compound formed by the reaction of ethanal with semicarbazide contains number of nitrogen atoms.
Answer
3
Solution
CH3-CH=O + H2N-NH- O \|C-NH2
H+ CH3-CH=N-NH- O \|C-NH2 + H2O
Product = ethanal semicarbazone ⇒ N atoms: =N–, –NH–, –NH₂
∴ 3 nitrogen atoms
Answer: 3