Thermodynamics

JEE Main 2024 (Online) 27th January Morning ShiftNumericalEasy📈 Topic in 29% papers+4

Ques. 1JEE Main 2024, 27 January (Morning Shift)

If three moles of an ideal gas at 300 K expand isothermally from 30 dm3 to 45 dm3 against a constant opposing pressure of 80 kPa, then the amount of heat transferred is J.

Answer

1200

Solution

Isothermal (ideal gas) ⇒ U = 0 ⇒ q = -w

Irreversible expansion: w = -pext V

w = -(80 103 Pa) (45-30) 10-3 m3

= -1200 J

∴ q = +1200 J (heat absorbed)

Answer: 1200

Keep practising — Thermodynamics

Ques. 2JEE Main 2024, 27 January (Evening Shift)

For a certain thermochemical reaction M N at T = 400 K, = 77.2 kJ mol-1, = 122 J K-1, log equilibrium constant (log K) is − 10-1.

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