For a certain thermochemical reaction M N at T = 400 K, = 77.2 kJ mol-1, = 122 J K-1, log equilibrium constant (log K) is − 10-1.
Answer
37
Solution
G = H - T S
= 77200 - 400 122
= 28400 J mol-1
G = -2.303 RT K
⇒ K = - 284002.303 8.314 400
= -3.708 = -37.08 10-1 ≈ -37 10-1
Answer: 37