Let ABC be an equilateral triangle. A new triangle is formed by joining the middle points of all sides of the triangle ABC and the same process is repeated infinitely many times. If P is the sum of perimeters and Q is the sum of areas of all the triangles formed in this process, then :
- P2 = 72 3Q
- P2 = 36 3Q
- P = 36 3Q2
- P2 = 6 3Q
Answer
(2) P2 = 36 3Q
Solution
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Let side of △ABC = a; ∵ mid-point theorem, each new side is half the previous one
Perimeters 3a, 3a2, 3a4, (G.P., r = 12) ⇒ P = 3a1 - 12 = 6a
Areas 34a2, 316a2, (G.P., r = 14) ⇒ Q = 34a21 - 14 = a2 3
Put a = P6: Q = P236 3
∴ P2 = 36 3Q
Answer: (2)