Heat of combustion Ho for C(s), H2(g) and CH4(g) are -94, -68 and -213 kcal/mol, then Ho for C(s) + 2H2(g) CH4(g) is
- -17 kcal
- -111 kcal
- -170 kcal
- -85 kcal
Answer
(1) -17 kcal
Solution
For a reaction, Ho = c Ho(reactants) - c Ho(products)
⇒ Ho = [ c Ho(C) + 2 c Ho(H2)] - c Ho(CH4)
⇒ Ho = [-94 + 2(-68)] - (-213)
= -230 + 213
∴ Ho = -17 kcal
Answer: (1)