A sample of gas at temperature T is adiabatically expanded to double its volume. Adiabatic constant for the gas is = 3/2. The work done by the gas in the process is: ( = 1 mole)
- RT[2 2 - 1]
- RT[2 - 2]
- RT[1 - 2 2]
- RT[ 2 - 2]
Answer
(2) RT[2 - 2]
Solution
Adiabatic: TV - 1 = constant
Tf = T ( V2V )1/2 = T 2
W = R(T - Tf) - 1 = RT (1 - 1 2 )1/2
= 2RT (1 - 1 2 )
= RT(2 - 2)
Answer: (2)