Consider the following chemical equilibrium of the gas phase reaction at a constant temperature : A(g) B(g) + C(g) If p is the total pressure, Kp is the pressure equilibrium constant and is the degree of dissociation, then which of the following is true at equilibrium?
- If Kp value is extremely high compared to p, becomes much less than unity
- When p increases, increases
- If p value is extremely high compared to Kp, 1
- When p increases, decreases
Answer
(4) When p increases, decreases
Solution
Take 1 mol of A initially.
At equilibrium: A = (1 - ), B = , C = ; total = (1 + ) mol
pA = 1 - 1 + p, pB = pC = 1 + p
Kp = pB pCpA = 2 p(1 + )(1 - ) = 2 p1 - 2
= KpKp + p
(1) Kp p 1, not much less than unity — incorrect.
(2), (4) At constant temperature Kp is constant; as p increases, KpKp + p decreases, so decreases (Le Chatelier: higher pressure favours the side with fewer gas moles, i.e. A). Hence (2) is incorrect and (4) is correct.
(3) p Kp Kpp 1, not 1 — incorrect.
Answer: (4)