At temperature T, compound AB2(g) dissociates as AB2(g) AB(g) + 12B2(g) having degree of dissociation x (small compared to unity). The correct expression for x in terms of Kp and p is:
- Kp
- [3] 2Kp2p
- [3] 2Kpp
- [4] 2Kpp
Answer
(2) [3] 2Kp2p
Solution
AB2 AB + 12B2
At equilibrium (moles): AB2: 1 - x, AB: x, B2: x2; total = 1 + x2
x 1 1 - x 1, 1 + x2 1
pAB2 p, pAB xp, pB2 xp2
Kp = pAB (pB2)1/2pAB2 = xp ( xp2 )1/2p = x3/2p1/2 2
x3/2 = 2 Kpp1/2
x3 = 2Kp2p
x = [3] 2Kp2p
Answer: (2)