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A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is 4 m, then the time period of small oscillations will be s. [take g= 2 m s-2]
8
g'= g(1+h/R)2= g4 ( h=R)
T=2 lg'=2 4 4 2
=2 4 =8 s
Answer: 8
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A simple harmonic oscillator has an amplitude A and time period 6 second. Assuming the oscillation starts from its mean position, the time required by it to travel from x=A to x= 32 A will be x s, where x= .
A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is cm, where = .