The mean and standard deviation of 100 observations are 40 and 5.1, respectively. By mistake one observation is taken as 50 instead of 40. If the correct mean and the correct standard deviation are and respectively, then 10( + ) is equal to
- 447
- 445
- 449
- 451
Answer
(3) 449
Solution
Incorrect: x = 100 40 = 4000
x2 = 100 (5.12 + 402 ) = 100(26.01 + 1600) = 162601
Correct: x = 4000 - 50 + 40 = 3990 = 39.9
x2 = 162601 - 2500 + 1600 = 161701
2 = 161701100 - (39.9)2 = 1617.01 - 1592.01 = 25 = 5
10( + ) = 10(39.9 + 5) = 449
Answer: (3)