Let x1, x2, , x10 be ten observations such that i=110(xi - 2) = 30, i=110(xi - )2 = 98, > 2, and their variance is 45. If and 2 are respectively the mean and the variance of 2(x1 - 1) + 4 , 2(x2 - 1) + 4 , , 2(x10 - 1) + 4 , then 2 is equal to :
- 100
- 90
- 120
- 110
Answer
(1) 100
Solution
(xi - 2) = 30 xi = 50, x = 5
Variance: xi210 - 25 = 45 xi2 = 258
(xi - )2 = xi2 - 2 xi + 10 2 = 98
258 - 100 + 10 2 = 98
2 - 10 + 16 = 0 = 2 or 8
> 2 = 8
New observations: yi = 2xi - 2 + 4 = 2xi + 30
= 2(5) + 30 = 40, 2 = 22 45 = 165
2 = 8 4016/5 = 100
Answer: (1)