The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is
- 2
- -2
- 1
- -1
Answer
(2) -2
Solution
Let rate = k[A]x[B]y
r2r1 = ( 2[B][B] )y = 2y
Rate decreases by a factor of 4: 2y = 14 = 2-2
y = -2
Answer: (2)