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Chemical Kinetics · Question 71

AIPMT 2001MCQMedium📈 Topic in 0% papers+4−1
1

When a bio-chemical reaction is carried out in laboratory, outside the human body in absence of enzyme, then rate of reaction obtained is 10-6 times, the activation energy of reaction in the presence of enzyme is

  1. 6/RT
  2. P is required
  3. different from Ea obtained in laboratory
  4. can't say anything.

Answer

(3) different from Ea obtained in laboratory

Solution

An enzyme is a biological catalyst; as per NCERT, a catalyst provides an alternative pathway of lower activation energy.

By the Arrhenius equation, k = A e-Ea/RT, so

kenzymeklab = e(Ea,lab - Ea,enzyme)/RT = 106

Ea,lab - Ea,enzyme = 2.303 6 RT, which is not zero.

The activation energy in the presence of enzyme is different from (lower than) the Ea obtained in the laboratory.

Answer: (3)

AIPMT 2001

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2

For the reaction; 2N2O5 4NO2 + O2 rate and rate constant are 1.02 10-4 and 3.4 10-5 s-1 respectively, then concentration of N2O5 at that time will be

  1. 1.732
  2. 3
  3. 1.02 10-4
  4. 3.4 105
AIPMT 2001
3

A human body required 0.01 m activity of radioactive substance after 24 hours. Half life of radioactive substance is 6 hours. Then injection of maximum activity of radioactive substance that can be injected is

  1. 0.08
  2. 0.04
  3. 0.16
  4. 0.32
AIPMT 2001
4

For the reaction 6H+ + BrO3- + 5Br- 3Br2 + 3H2O which of the following relation correctly represents the consumption and formation of products.

  1. d[Br2]dt = - 35 d[Br-]dt
  2. d[Br2]dt = 35 d[Br-]dt
  3. d[Br2]dt = - 53 d[Br-]dt
  4. d[Br2]dt = 53 d[Br-]dt
AIPMT 2000
5

A 300 g radioactive sample has a half-life of 3 hours. After 18 hours, the remaining quantity is

  1. 4.68 g
  2. 2.34 g
  3. 3.34 g
  4. 9.37 g
AIPMT 2000

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