A spherical planet has a mass MP and diameter DP. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
- 4GMPDP2
- GMP mDP2
- GMPDP2
- 4GMP mDP2
Answer
(1) 4GMPDP2
Solution
Acceleration due to gravity at the surface: g = GMPRP2
RP = DP2
g = GMP(DP/2)2 = 4GMPDP2
(g does not depend on the mass m of the falling particle.)
Answer: (1)