The height at which the weight of a body becomes ( 116 )th of its weight on the surface of earth (radius R), is
- 5R
- 15R
- 3R
- 4R
Answer
(3) 3R
Solution
At height h: gh = g ( RR + h )2
Weight becomes 116 of the surface value:
( RR + h )2 = 116
RR + h = 14
R + h = 4R
h = 3R
Answer: (3)