The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then [figure]
- t1 = 4t2
- t1 = 2t2
- t1 = t2
- t1 > t2
Answer
(2) t1 = 2t2
Solution
By Kepler's law of areas, the line joining the sun to the planet sweeps out equal areas in equal intervals of time, i.e. the areal velocity A t is constant.
t area swept
t1t2 = area SCDarea SAB = 2
t1 = 2t2
Answer: (2)