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d- and f-Block Elements · Question 74

AIPMT 2002MCQEasy📈 Topic in 25% papers+4−1
1

General electronic configuration of lanthanides is

  1. (n-2)f1-14 (n-1)s2p6d0-1 ns2
  2. (n-2)f0-14 (n-1)d0-1 ns2
  3. (n-2)f0-14 (n-1)d10 ns2
  4. (n-2)d0-1 (n-1)f1-14 ns2

Answer

(1) (n-2)f1-14 (n-1)s2p6d0-1 ns2

Solution

Lanthanides (Ce to Lu) are 4f-series elements of period 6 (n = 6).

As per NCERT, their general electronic configuration is [Xe] 4f1-14 5d0-1 6s2.

4f = (n-2)f1-14, the completely filled 5s and 5p = (n-1)s2p6, 5d = (n-1)d0-1 and 6s = ns2

General configuration: (n-2)f1-14 (n-1)s2p6d0-1 ns2

Option (2) and (3) wrongly allow f0 (or d10), and option (4) interchanges the f and d shells.

Answer: (1)

AIPMT 2002

Keep practising — d- and f-Block Elements

2

Which of the following shows maximum number of oxidation states?

  1. Cr
  2. Fe
  3. Mn
  4. V
AIPMT 2002
3

Which of the following statements is not correct?

  1. La(OH)3 is less basic than Lu(OH)3.
  2. In lanthanide series ionic radius of Ln3+ ion decreases.
  3. La is actually an element of transition series rather than lanthanides.
  4. Atomic radii of Zr and Hf are nearly the same because of lanthanide contraction.
AIPMT 2001
4

Which of the following shows maximum number of oxidation states?

  1. Cr
  2. Fe
  3. Mn
  4. V
AIPMT 2000
5

Which ion is colourless?

  1. Cr4+
  2. Sc3+
  3. Ti3+
  4. V3+
AIPMT 2000

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