A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle of 30 with the wall. It is reflected with the same speed at the same angle. If the ball is in contact with the wall for 0.25 seconds, the average force acting on the wall is :
- 96 N
- 48 N
- 24 N
- 12 N
Answer
(3) 24 N
Solution
Component of velocity perpendicular to the wall = v 30 = 12 12 = 6 m/s
The component parallel to the wall is unchanged; the perpendicular component reverses.
Change in momentum = 2mv 30 = 2 0.5 6 = 6 kg m/s
Average force = p t = 60.25 = 24 N
Answer: (3)