An object of mass 3 kg is at rest. Now a force of F = 6t2 i + 4t j is applied on the object then velocity of object at t = 3 sec. is
- 18 i + 3 j
- 18 i + 6 j
- 3 i + 18 j
- 18 i + 4 j
Answer
(2) 18 i + 6 j
Solution
m d vdt = F
3 v = 03 (6t2 i + 4t j) dt
= [2t3 i + 2t2 j ]03
= 54 i + 18 j
v = 18 i + 6 j
Answer: (2)