A block of mass 10 kg placed on rough horizontal surface having coefficient of friction = 0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be
- 10 m/s2
- 5 m/s2
- 15 m/s2
- 0.5 m/s2
Answer
(2) 5 m/s2
Solution
Kinetic friction: f = mg = 0.5 10 10 = 50 N (taking g = 10 m/s2)
100 N > 50 N, the block moves.
a = F - fm = 100 - 5010
= 5 m/s2
Answer: (2)