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p-Block Elements (Group 15–18) · Question 8

JEE Advanced 2024 Paper 1MatchingEasy📈 Topic in 17% papers+4−1
1

Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.

  1. P-5, Q-2, R-3, S-1
  2. P-5, Q-3, R-2, S-4
  3. P-4, Q-3, R-2, S-1
  4. P-4, Q-2, R-5, S-3

Answer

(2) P-5, Q-3, R-2, S-4

Solution

Electron-pair geometry follows from (bond pairs + lone pairs) on Xe; π bonds of Xe=O are not counted.

XeF2: 2 bp + 3 lp = 5 → trigonal bipyramidal, three lone pairs → 5.

XeF4: 4 bp + 2 lp = 6 → octahedral, two lone pairs → 3.

XeO3: 3 σ bp + 1 lp = 4 → tetrahedral, one lone pair → 2.

XeO3F2: 5 σ bp + 0 lp → trigonal bipyramidal, no lone pair → 4.

P-5, Q-3, R-2, S-4

Answer: (B)

JEE Advanced 2024 Paper 1

Keep practising — p-Block Elements (Group 15–18)

2

The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are

  1. [PF4]+[PF6]- and [PCl4]+[PF6]-
  2. [PCl4]+[PCl4F2]- and [PCl4]+[PF6]-
  3. PF3 and PCl3
  4. PF5 and PCl3
JEE Advanced 2024 Paper 2
3

The compound(s) having peroxide linkage is(are)

  1. H2S2O7
  2. H2S2O8
  3. H2S2O5
  4. H2SO5
JEE Advanced 2024 Paper 2

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