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The number of ways, in which 16 oranges can be distributed to four children such that each child gets at least one orange, is
(4) 455
The oranges are identical. Let the children get x1, x2, x3, x4 oranges:
x1 + x2 + x3 + x4 = 16, xi 1
Put xi = yi + 1 (yi 0): y1 + y2 + y3 + y4 = 12
Number of solutions = 12+4-1C4-1 = 15C3
= 15 14 136 = 455
Answer: (4)
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