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Moving Charges and Magnetism

JEE Main 2025 (Online) 24th January Evening ShiftNumericalMedium📈 Topic in 24% papers+4
Ques. 1JEE Main 2025, 24 January (Evening Shift)

A tightly wound long solenoid carries a current of 1.5 A. An electron is executing uniform circular motion inside the solenoid with a time period of 75 ns. The number of turns per metre in the solenoid is . [Take mass of electron me=9 10-31 kg, charge of electron |qe|=1.6 10-19 C, 0=4 10-7 NA2, 1 ns=10-9 s]

Answer

250

Solution

The electron circles with T= 2 mqB and B= 0nI inside the solenoid.

[figure]

n= 2 mqT 0I= 2 9 10-311.6 10-19 75 10-9 4 10-7 1.5

= 7.5 10-53 10-7

=250 turns per metre

Answer: 250

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Ques. 2JEE Main 2025, 23 January (Morning Shift)

Consider a moving coil galvanometer (MCG): Choose the correct answer from the options given below:

  1. A, D Only
  2. A, B Only
  3. A, B, E Only
  4. B, D, E Only
Ques. 3JEE Main 2025, 23 January (Evening Shift)

A galvanometer having a coil of resistance 30 need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be 30X , where X is

  1. 447
  2. 298
  3. 149
  4. 596
Ques. 4JEE Main 2025, 22 January (Evening Shift)

An electron projected perpendicular to a uniform magnetic field B moves in a circle. If Bohr's quantization is applicable, then the radius of the electronic orbit in the first excited state is :

  1. h eB
  2. 4h eB
  3. h2 eB
  4. 2h eB
Ques. 5JEE Main 2025, 22 January (Evening Shift)

A proton is moving undeflected in a region of crossed electric and magnetic fields at a constant speed of 2 105 m s-1. When the electric field is switched off, the proton moves along a circular path of radius 2 cm . The magnitude of electric field is x 104 N/C. The value of x is . Take the mass of the proton =1.6 10-27 kg.

Ques. 6JEE Main 2025, 22 January (Evening Shift)

Two long parallel wires X and Y, separated by a distance of 6 cm , carry currents of 5 A and 4A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is x 10-5 T. The value of x is . Take permeability of free space as 0=4 10-7 SI units. [figure]

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