A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will
- increase four times
- be reduced to half
- remain the same
- be doubled
Answer
(3) remain the same
Solution
By Gauss's law, = Q 0
The flux depends only on the charge enclosed, not on the size or shape of the closed surface.
On doubling the radius, the flux remains the same.
Answer: (3)