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Amines · Question 54

AIPMT 2004MCQEasy📈 Topic in 38% papers+4−1
1

In a reaction of aniline a coloured product C was obtained. [figure] The structure of C would be

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(2) [figure]

Solution

Step 1 (diazotisation): as per NCERT, aniline reacts with nitrous acid (NaNO2 + HCl) at 273–278 K to give benzenediazonium chloride (B):

C6H5NH2 + NaNO2 + 2HCl C6H5N2+Cl- + NaCl + 2H2O

Step 2 (coupling): the diazonium ion is a weak electrophile and attacks the para position of the strongly activated ring of N,N-dimethylaniline in the cold:

C6H5N2+Cl- + C6H5N(CH3)2 C6H5-N=N-C6H4-N(CH3)2 + HCl

C is p-(N,N-dimethylamino)azobenzene, a yellow azo dye; the -N=N- group joins the two rings, and the -N(CH3)2 group stays para to it.

Answer: (2)

AIPMT 2004

Keep practising — Amines

2

The final product C, obtained in this reaction [figure] would be

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2003
3

CH3CH2Cl NaCN X Ni/H2 Y acetic anhydride Z Z in the above reaction sequence is

  1. CH3CH2CH2NHCOCH3
  2. CH3CH2CH2NH2
  3. CH3CH2CH2CONHCH3
  4. CH3CH2CH2CONHCOCH3
AIPMT 2002
4

Intermediates formed during reaction of [figure] with Br2 and KOH are

  1. RCONHBr and RNCO
  2. RNHCOBr and RNCO
  3. RNH-Br and RCONHBr
  4. RCONBr2
AIPMT 2001
5

A reduction B CHCl3/KOH C reduction N-methylaniline then A is

  1. [figure]
  2. [figure]
  3. CH3NH2
  4. [figure]
AIPMT 2000

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