A container contains a liquid with refractive index of 1.2 up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 40 cm. The value of H is cm. (Consider liquids are immiscible)
Answer
80
Solution
Normal shift produced by a layer of thickness t and refractive index : = t (1 - 1 )
Total shift = 60 (1 - 11.2 ) + H (1 - 11.6 )
⇒ 40 = 60 16 + H 38
⇒ 40 = 10 + 3H8
⇒ H = 30 83 = 80 cm
Answer: 80