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Aldehydes, Ketones and Carboxylic Acids · Question 8

JEE Advanced 2025 Paper 2MCQMedium📈 Topic in 17% papers+4−1
1

The correct reaction/reaction sequence that would produce a dicarboxylic acid as the major product is

  1. [figure] [ (iii) H3O+] (i) NaCN; (ii) HO-, H2O
  2. arraycCHO\ |\ (CHOH)4\ |\ CH2OH array Br2, H2O
  3. [figure] [(ii) KMnO4, H2SO4, ](i) KOH, EtOH
  4. [figure] H2CrO4

Answer

(3) [figure] [(ii) KMnO4, H2SO4, ](i) KOH, EtOH

Solution

(A) Cyanide replaces Cl; the nitrile is hydrolysed to –COOH; the –OH stays:

[figure] NaCN [figure] [ H3O+] HO-, H2O [figure]

3-Hydroxypropanoic acid – a monocarboxylic acid.

(B) Bromine water (mild oxidant) oxidises only the –CHO group of glucose:

arraycCHO\ |\ (CHOH)4\ |\ CH2OH array Br2, H2O arraycCOOH\ |\ (CHOH)4\ |\ CH2OH array

Gluconic acid – a monocarboxylic acid.

(C) Alcoholic KOH gives cyclohexene (dehydrohalogenation); hot acidic KMnO4 cleaves the C=C and oxidises both ends to –COOH:

[figure] KOH, EtOH [figure] KMnO4, H2SO4, [figure]

Adipic acid (hexanedioic acid) – a dicarboxylic acid.

(D) Chromic acid oxidises the 1° alcohol to –COOH; the ketone is not oxidised:

[figure] H2CrO4 [figure]

A keto monocarboxylic acid.

Answer: (C)

JEE Advanced 2025 Paper 2

Keep practising — Aldehydes, Ketones and Carboxylic Acids

2

Monocyclic compounds P, Q, R and S are the major products formed in the reaction sequences given below. [figure] The product having the highest number of unsaturated carbon atom(s) is

  1. P
  2. Q
  3. R
  4. S
JEE Advanced 2025 Paper 2
3

Reaction of iso-propylbenzene with O2 followed by the treatment with H3O+ forms phenol and a by-product P. Reaction of P with 3 equivalents of Cl2 gives compound Q. Treatment of Q with Ca(OH)2 produces compound R and calcium salt S. The correct statement(s) regarding P, Q, R and S is(are)

  1. Reaction of P with R in the presence of KOH followed by acidification gives [figure]
  2. Reaction of R with O2 in the presence of light gives phosgene gas
  3. Q reacts with aqueous NaOH to produce Cl3CCH2OH and Cl3CCOONa
  4. S on heating gives P
JEE Advanced 2024 Paper 1
4

Complete reaction of acetaldehyde with excess formaldehyde, upon heating with conc. NaOH solution, gives P and Q. Compound P does not give Tollens’ test, whereas Q on acidification gives positive Tollens’ test. Treatment of P with excess cyclohexanone in the presence of catalytic amount of p-toluenesulfonic acid (PTSA) gives product R. Sum of the number of methylene groups (-CH2-) and oxygen atoms in R is .

JEE Advanced 2024 Paper 1
5

List-I contains various reaction sequences and List-II contains the possible products. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

  1. P-3, Q-5, R-4, S-1
  2. P-3, Q-2, R-4, S-1
  3. P-3, Q-5, R-1, S-4
  4. P-5, Q-2, R-4, S-1
JEE Advanced 2024 Paper 1
6

In the following reaction sequence, the major product P is formed. [figure] Glycerol reacts completely with excess P in the presence of an acid catalyst to form Q. Reaction of Q with excess NaOH followed by the treatment with CaCl2 yields Ca-soap R, quantitatively. Starting with one mole of Q, the amount of R produced in gram is . [Given, atomic weight: H = 1, C = 12, N = 14, O = 16, Na = 23, Cl = 35, Ca = 40]

JEE Advanced 2024 Paper 1
7

The option(s) with correct sequence of reagents for the conversion of P to Q is(are) [figure]

  1. i) Lindlar’s catalyst, H2; ii) SnCl2/HCl; iii) NaBH4; iv) H3O+
  2. i) Lindlar’s catalyst, H2; ii) H3O+; iii) SnCl2/HCl; iv) NaBH4
  3. i) NaBH4; ii) SnCl2/HCl; iii) H3O+; iv) Lindlar’s catalyst, H2
  4. i) Lindlar’s catalyst, H2; ii) NaBH4; iii) SnCl2/HCl; iv) H3O+
JEE Advanced 2024 Paper 2
8

Sum of number of oxygen atoms in S and T is .

JEE Advanced 2024 Paper 2

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