Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of electron in this orbit is E/x, then x = (Given a0 = 0.529 Å, E = energy of electron in ground state).
Answer
16
Solution
rn = n2a0 (Z = 1) n2 = 8.480.529 16 n = 4
En = En2 E4 = E16
x = 16
Answer: 16