Let f(x) = x2025 - x2000, x [0, 1] and the minimum value of the function f(x) in the interval [0, 1] be (80)80(n)-81. Then n is equal to
- -40
- -41
- -80
- -81
Answer
(4) -81
Solution
f'(x) = 2025x2024 - 2000x1999 = x1999(2025x25 - 2000)
f'(x) = 0 x25 = 20002025 = 8081
f'(x) < 0 before and > 0 after this point, so it gives the minimum (f(0) = f(1) = 0).
f(x) = x2000(x25 - 1) = ( 8081 )80 ( 8081 - 1 )
= - 80808180 181 = - 80808181
= (80)80(-81)-81 ( (-81)81 = -8181)
n = -81
Answer: (4)