A capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of the water in the capillary is 5 g. Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is :
- 5.0 g
- 10.0 g
- 20.0 g
- 2.5 g
Answer
(2) 10.0 g
Solution
Capillary rise: h = 2S r g ⇒ h 1r
Mass of water raised: m = r2 h
⇒ m r2 1r = r
∴ m2m1 = 2rr = 2
⇒ m2 = 2 5 = 10.0 g
Answer: (2)