A small hole of area of cross-section 2 mm2 is present near the bottom of a fully filled open tank of height 2 m. Taking g = 10 m/s2, the rate of flow of water through the open hole would be nearly :
- 8.9 10-6 m3/s
- 2.23 10-6 m3/s
- 6.4 10-6 m3/s
- 12.6 10-6 m3/s
Answer
(4) 12.6 10-6 m3/s
Solution
By Torricelli's law (speed of efflux), v = 2gh
v = 2 10 2 = 40 6.32 m/s
Rate of flow, Q = Av
= (2 10-6) 6.32
12.6 10-6 m3/s
Answer: (4)