Which among the given molecules can exhibit tautomerism? [figure]
- III only
- Both I and III
- Both I and II
- Both II and III
Answer
(1) III only
Solution
Keto–enol tautomerism needs an α-H atom that can shift to O to form a C=C (enol).
I: both α-carbons are bridgehead carbons ⇒ a C=C at a bridgehead of this small bicyclic ring is too strained (Bredt's rule) ⇒ no enol.
II: one α-carbon is a bridgehead (no enol possible) and the other carries two Ph groups (no α-H) ⇒ no enol.
III: the α-CH2 group has α-H atoms ⇒ enol is formed ⇒ tautomerism.
∴ III only.
Answer: (1)