Number of isomeric alcohols of molecular formula C6H14O which give positive iodoform test is
- three
- four
- five
- two
Answer
(2) four
Solution
Iodoform test is given by alcohols having the CH3-CH(OH)-R unit.
For C6H14O ⇒ R = C4H9, which has four isomeric forms:
(i) CH3CH(OH)CH2CH2CH2CH3 (hexan-2-ol)
(ii) CH3CH(OH)CH2CH(CH3)2 (4-methylpentan-2-ol)
(iii) CH3CH(OH)CH(CH3)CH2CH3 (3-methylpentan-2-ol)
(iv) CH3CH(OH)C(CH3)3 (3,3-dimethylbutan-2-ol)
∴ Number of such alcohols = 4
Answer: (2)