The angle of projection of a particle is measured from the vertical axis as and the maximum height reached by the particle is hm. Here hm as function of can be presented as
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Answer
(4) [figure]
Solution
Vertical component of velocity = u
hm = u2 2 2g
At = 0: hm = u22g (maximum, with zero slope since dhmd = - u2 2 2g = 0)
At = 90 : hm = 0
hm starts at its maximum value, decreases as increases and becomes zero at = 90 , as shown in option (4).
Answer: (4)