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Motion in a Plane · Question 14

JEE Main 2025 (Online) 3rd April Morning ShiftMCQEasy📈 Topic in 39% papers+4−1
1

The angle of projection of a particle is measured from the vertical axis as and the maximum height reached by the particle is hm. Here hm as function of can be presented as

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(4) [figure]

Solution

Vertical component of velocity = u

hm = u2 2 2g

At = 0: hm = u22g (maximum, with zero slope since dhmd = - u2 2 2g = 0)

At = 90 : hm = 0

hm starts at its maximum value, decreases as increases and becomes zero at = 90 , as shown in option (4).

Answer: (4)

JEE Main 2025 (Online) 3rd April Morning Shift

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2

A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as nu225g, where value of n is: (Given, 'g' is the acceleration due to gravity.)

  1. 6
  2. 12
  3. 18
  4. 24
JEE Main 2025 (Online) 3rd April Evening Shift
3

A river is flowing from west to east direction with speed of 9 km h-1. If a boat capable of moving at a maximum speed of 27 km h-1 in still water, crosses the river in half a minute, while moving with maximum speed at an angle of 150 to direction of river flow, then the width of the river is :

  1. 112.5 m
  2. 75 m
  3. 300 m
  4. 112.5 3 m
JEE Main 2025 (Online) 2nd April Morning Shift
4

Two projectiles are fired with same initial speed from same point on ground at angles of (45 - ) and (45 + ), respectively, with the horizontal direction. The ratio of their maximum heights attained is :

  1. 1+ 1-
  2. 1+ 2 1- 2
  3. 1- 1+
  4. 1- 2 1+ 2
JEE Main 2025 (Online) 29th January Morning Shift
5

The maximum speed of a boat in still water is 27 km/h. Now this boat is moving downstream in a river flowing at 9 km/h. A man in the boat throws a ball vertically upwards with speed of 10 m/s. Range of the ball as observed by an observer at rest on the bank is cm. (Take g = 10 m/s2)

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