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A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as nu225g, where value of n is: (Given, 'g' is the acceleration due to gravity.)
(4) 24
R = u2 2 g, H = u2 2 2g
R = 3H 2u2 g = 3u2 2 2g
= 43 = 45, = 35
2 = 2 45 35 = 2425
R = 24u225g n = 24
Answer: (4)
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Two projectiles are fired with same initial speed from same point on ground at angles of (45 - ) and (45 + ), respectively, with the horizontal direction. The ratio of their maximum heights attained is :
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