Pre-exponential factors of two different reactions of same order are identical. Let activation energy of first reaction exceed the activation energy of second reaction by 20 kJ mol-1. If k1 and k2 are the rate constants of first and second reaction respectively at 300 K, then k2k1 will be . (nearest integer) [R = 8.3 J K-1 mol-1]
Answer
8
Solution
By Arrhenius equation, k = A e-Ea/RT
k1 = A e-Ea1/RT and k2 = A e-Ea2/RT (same A)
k2k1 = e(Ea1 - Ea2)/RT
k2k1 = Ea1 - Ea2RT
= 20 10008.3 300
= 200002490 = 8.03 8
Answer: 8