In a first order decomposition reaction, the time taken for the decomposition of reactant to one fourth and one eighth of its initial concentration are t1 and t2 (s), respectively. The ratio t1/t2 will be:
- 43
- 32
- 34
- 23
Answer
(4) 23
Solution
For a first order reaction:
t = 2.303k [R]0[R]
Reactant reduced to one fourth: [R] = [R]04
t1 = 2.303k 4 = 2.303k 2 2
Reactant reduced to one eighth: [R] = [R]08
t2 = 2.303k 8 = 2.303k 3 2
t1t2 = 2 23 2 = 23
(Equivalently, t1 = 2t1/2 and t2 = 3t1/2.)
Answer: (4)