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Application of Integrals · Question 4

JEE Advanced 2025 Paper 2Multiple CorrectHard📈 Topic in 33% papers+4−1
1

Let S denote the locus of the mid-points of those chords of the parabola y2=x, such that the area of the region enclosed between the parabola and the chord is 43. Let R denote the region lying in the first quadrant, enclosed by the parabola y2=x, the curve S, and the lines x=1 and x=4. Then which of the following statements is (are) TRUE?

  1. (4, 3) S
  2. (5, 2) S
  3. Area of R is 143-2 3
  4. Area of R is 143- 3

Answer

(1) (4, 3) S, (3) Area of R is 143-2 3

Solution

Chord ends (t12,t1),(t22,t2); area between parabola x=y2 and chord = |t1-t2|36= 43 |t1-t2|=2.

Mid-point: k= t1+t22, h= t12+t222= (t1+t2)2+(t1-t2)24=k2+1.

S: x=y2+1. (4, 3): 3+1=4 (true); (5, 2): 3 5.

Area of R= 14 ( x- x-1 )dx= 23(8-1)- 23 3 3= 143-2 3

Answer: (A), (C)

JEE Advanced 2025 Paper 2

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2

Let S= \(x,y) R R: x 0, y 0, y2 4x, y2 12-2x and 3y+ 8 x 5 8 \. If the area of the region S is 2, then is equal to

  1. 172
  2. 173
  3. 174
  4. 175
JEE Advanced 2024 Paper 2

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