A wire of resistance 20 is divided into 10 equal parts. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is .
Answer
5
Solution
R l: each part = 2010 = 2
One pair in parallel: 2 22 + 2 = 1 ; 10 parts ⇒ 5 pairs
5 pairs in series: Req = 5 1 = 5
Answer: 5