The ratio of heat dissipated per second through the resistance 5 and 10 in the circuit given below is: [figure]
- 4 : 1
- 2 : 1
- 1 : 2
- 1 : 1
Answer
(2) 2 : 1
Solution
5 and 10 are in parallel ⇒ same potential difference V across both.
Heat per second: H = V2R
H5H10 = R10R5 = 105 = 2 : 1
Answer: (2)