A paratrooper jumps from an aeroplane and opens a parachute after 2 s of free fall and starts decelerating with 3 m/s2. At 10 m height from ground, while descending with the help of parachute, the speed of paratrooper is 5 m/s. The initial height of the airplane is m. (g = 10 m/s2)
- 92.5
- 62.5
- 20
- 82.5
Answer
(1) 92.5
Solution
Free fall for 2 s: v1 = gt = 10 2 = 20 m/s
h1 = 12gt2 = 12 10 4 = 20 m
With parachute (retardation 3 m/s2) until speed is 5 m/s:
v2 = v12 - 2ah2 25 = 400 - 6h2
h2 = 3756 = 62.5 m
This point is 10 m above the ground.
Initial height = 20 + 62.5 + 10 = 92.5 m
Answer: (1)