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The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between t = 0 to t = 4 s? [figure]
(2) 30 m
Velocity is positive throughout, so distance = area under the v–t graph.
From 0 to 2 s (triangle OA): 12 2 10 = 10 m
From 2 s to 4 s (rectangle under AB): 2 10 = 20 m
distance = 10 + 20 = 30 m
Answer: (2)
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